crypt code i

-AMMENDMENT VERSION---
My dear friends,
Just want to share my knowledge, may it brought upon me continuous amal jariah,
Recently, I have doing trial and error of creating encrypt code and through reading and experiments, hereby I have found that
IF AND ONLY IF n>7, it must be simplified to nearest number as not exceeds 7 and by using conversion of base 8 to base 2 (421 concepts,modern mathematics form 4, chapter 1) therefore resulting a encrypt code base on alphabatical roman order of number. It is proved.

TABLE OF SEVENIZATON
 A: 1
B: 2
C:3
D:4
E:5
F:6
G:7
H:7+1
I: 7+2
J:7+3
K:7+4
L:7+5
M:7+6
N:7+7
O:7+7+1
P:7+7+2
Q:7+7+3
R:7+7+4
S:7+7+5
T:7+7+6
U:7+7+7
V:7+7+7+1
W:7+7+7+2
X:7+7+7+3
Y:7+7+7+4
Z:7+7+7+5

RULE:
1) MAKE PHRASES, CHANGE IT TO NUMERICAL FORM (exp: abc: 123)
2) FOLLOW ACCORDING TO THE TABLE ABOVE
3) CONVERT TO BINARY FORM(101101) BY CONVERTING THE NUMBER WE HAVE DEVELOP USING 421 CONCEPT( TURN BASE 8 TO BASE 2)

-421 or 4+2+1  CONCEPTS:
EXP:  bas

b:2-----421--->010
a:1-----421--->001
s:7+7+5-----421---->111/111/101  as (4+2+1/4+2+1/4+0+1)
       therefore: 010,001,2(111)101,;